There was a total of 756 visitors at the zoo.
Number of children visitors is three times the number of adult visitors.
How many more children than adults were there?
Let's define variables for the number of adults and children:
Let the number of adults = A.
Since there were 3 times as many children as adults, the number of children is 3A.
The total number of visitors:
A+3A=756
Step 1: Solve for A
4A=756
A=756 ÷ 4 = 189
Step 2: Find the Number of Children
3A=3×189=567
Step 3: Find How Many More Children than Adults
567−189=378
Thus, there were 378 more children than adults at the zoo. ✅
Joey has 76 sweets.
She packs all the sweets into bags of 3 sweets or bags of 5 sweets.
She has 20 bags of sweets after packing.
How many bags of 3 sweets are there?
Let's define variables:
Let x be the number of bags with 3 sweets.
Let y be the number of bags with 5 sweets.
We know:
Total number of bags: x+y=20
Total number of sweets: 3x+5y=76
Step 1: Find y
From the first equation:
y=20−x
Step 2: Substitute into the second equation
3x+5(20−x)=76
Step 3: Expand and solve for x
3x+100−5x=76
−2x+100=76
−2x=76−100
−2x=−24
x=24÷2=12
Step 4: Find y
y=20−12=8
Thus, there are 12 bags of 3 sweets. ✅
The sum of 2 numbers is 86.
The difference between the 2 number is 14.
Find the smaller number.
Let the two numbers be xx and yy, where x is the larger number and y is the smaller number.
We are given:
Sum of the numbers: x+y=86
Difference between the numbers: x−y=14
Step 1: Add the two equations
(x+y)+(x−y)=86+14
2x=100
x=100÷2=50
Step 2: Solve for y
y=86−x=86−50=36
Thus, the smaller number is 36. ✅